Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 8 - Cumulative Review Exercises - Page 952: 1


The solution is, $\underline{x=\frac{-1\pm \sqrt{33}}{4}}$.

Work Step by Step

Consider the given equation, $\begin{align} & 2{{x}^{2}}=4-x \\ & 2{{x}^{2}}+x-4=0 \\ & x=\frac{-1\pm \sqrt{{{1}^{2}}-4\left( -4 \right)\left( 2 \right)}}{2\times 2} \\ & =\frac{-1\pm \sqrt{33}}{4} \end{align}$ The solutions of the equations are $x=\frac{-1\pm \sqrt{33}}{4}$.
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