Answer
The required equation is, $1682=16a+4b+c$.
Work Step by Step
It is provided that:
x in $y=a{{x}^{2}}+bx+c$ is 4;
The value of y is 1682.
Substitute the value of x in the given equation:
$\begin{align}
& 1682=a{{\left( 4 \right)}^{2}}+4b+c \\
& 1682=16a+4b+c \\
\end{align}$
Thus, the solution is $1682=16a+4b+c$.
