Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Section 7.1 - Systems of Linear Equations in Two Variables - Exercise Set - Page 823: 116


The equation is, $11x+4y=-3$.

Work Step by Step

By multiplying equation (II) by 2 and adding into equation (I), we get: $\begin{align} & 5x-2y-4z=3 \\ & \underline{6x+6y+4z=-6} \\ & \underline{11x+4y+0z=-3} \\ \end{align}$ Thus, the equation becomes $11x+4y=-3$.
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