## Precalculus (6th Edition) Blitzer

The ordered triple $\left( x,y,z \right)$ satisfies the equation $2x-y+4z=-8$
It is provided that: $x=3,y=2\text{ and }z=-3\$ And we must satisfy the equation $2x-y+4z=-8$ Now, put the values of x, y and z in the equation, \begin{align} & 2\left( 3 \right)-\left( 2 \right)+4\left( -3 \right)=-8 \\ & 6-2-12=-8 \\ & 6-14=-8 \\ & -8=-8 \end{align} Thus, the ordered triple $\left( x,y,z \right)$ satisfies the equation $2x-y+4z=-8$