## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 7 - Cumulative Review Exercises - Page 879: 9

#### Answer

The graph is shown below: #### Work Step by Step

We know that the graph of the function $g\left( x \right)=f\left( x+2 \right)-1$ can be plotted as given below: When the real positive number is c, then the graph of $f\left( x+c \right)$ is the graph of $f\left( x \right)$ shifted towards the left with c units and the graph of $f\left( x-c \right)$ is the graph of $f\left( x \right)$ shifted towards the right with c units. And for a positive integer a, the graph of $f\left( x \right)+a$ is the graph of $f\left( x \right)$ shifted upwards with a units and the graph of $f\left( x \right)-a$ is the graph of $f\left( x \right)$ shifted downwards with a units. Then, the graph of $f\left( x+2 \right)-1$ would correspond to the graph of $f\left( x \right)$ shifted towards 2 units to the left and 1 unit downwards. So, plot the graph as given below: After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.