Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Cumulative Review Exercises - Page 879: 9

Answer

The graph is shown below:
1570279805

Work Step by Step

We know that the graph of the function $ g\left( x \right)=f\left( x+2 \right)-1$ can be plotted as given below: When the real positive number is c, then the graph of $ f\left( x+c \right)$ is the graph of $ f\left( x \right)$ shifted towards the left with c units and the graph of $ f\left( x-c \right)$ is the graph of $ f\left( x \right)$ shifted towards the right with c units. And for a positive integer a, the graph of $ f\left( x \right)+a $ is the graph of $ f\left( x \right)$ shifted upwards with a units and the graph of $ f\left( x \right)-a $ is the graph of $ f\left( x \right)$ shifted downwards with a units. Then, the graph of $ f\left( x+2 \right)-1$ would correspond to the graph of $ f\left( x \right)$ shifted towards 2 units to the left and 1 unit downwards. So, plot the graph as given below:
Small 1570279805
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