## Precalculus (6th Edition) Blitzer

The required value of $fof\left( -1 \right)$ is $\underline{3}$.
From the given graph: $fof\left( -1 \right)=f\left( f\left( -1 \right) \right)$ where, $f\left( -1 \right)=0$ So, \begin{align} & fof\left( -1 \right)=f\left( f\left( -1 \right) \right) \\ & fof\left( -1 \right)=f\left( 0 \right) \\ & =3 \end{align} Since, $f\left( 0 \right)=3$ $f\left( f\left( -1 \right) \right)=3$ Therefore, the value of $f\left( f\left( -1 \right) \right)=\underline{3}$.