Precalculus (6th Edition) Blitzer

Published by Pearson

Chapter 6 - Section 6.7 - The Dot Product - Exercise Set - Page 799: 83

Answer

Step 1. See figure. Step 2. $\sqrt {29}$

Work Step by Step

Step 1. Given $\vec v=5i-2j$, we can sketch the vector as shown in the figure. Step 2. We can find the magnitude of the vector as $|\vec v|=\sqrt {(5)^2+(-2)^2}=\sqrt {29}$

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