Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.7 - The Dot Product - Exercise Set - Page 799: 60

Answer

Step 1. See figure. Step 2. $5cos(\frac{3\pi}{2})+5i\ sin(\frac{3\pi}{2})$

Work Step by Step

Step 1. Given the complex number $-5i$, we can identify $a=0, b=-5$ as $(0,-5)$ in complex coordinates as shown in the figure. Step 2. Using the above results, we can get the modulus as $r=\sqrt {a^2+b^2}=\sqrt {(0)^2+(-5)^2}=5$. The polar angle can be found as $\theta=\frac{3\pi}{2} $ (on negative y-axis). Thus, we can write the complex number in polar form as $-5i=5cos(\frac{3\pi}{2})+5i\ sin(\frac{3\pi}{2})$
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