Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.5 - Complex Numbers in Polar Form; DeMoivre's Theorem - Exercise Set - Page 768: 56

Answer

The power of the given complex number in the rectangular form is $-4+4\sqrt{3}i$.

Work Step by Step

Consider the given complex number in the polar form, ${{\left[ 2\left( \cos 40{}^\circ +i\sin 40{}^\circ \right) \right]}^{3}}$ If n is a positive integer, then ${{z}^{n}}$ is, $\begin{align} & {{z}^{n}}={{\left[ r\left( \cos \theta +i\sin \theta \right) \right]}^{n}} \\ & ={{r}^{n}}\left( \cos n\theta +i\sin n\theta \right) \end{align}$ That is., ${{z}^{n}}={{r}^{n}}\left( \cos n\theta +i\sin n\theta \right)$ …… (1) Now, for the given complex number, using (1) to get, $\begin{align} & z={{\left[ 2\left( \cos 40{}^\circ +i\sin 40{}^\circ \right) \right]}^{3}} \\ & z={{2}^{3}}\left( \cos 3\times 40{}^\circ +i\sin 3\times 40{}^\circ \right) \\ & z=8\left( \cos 120{}^\circ +i\sin 120{}^\circ \right) \\ & z=8\left( -\frac{1}{2}+i\frac{\sqrt{3}}{2} \right) \\ \end{align}$ Simplifying it further, to get, $z=-4+4\sqrt{3}i$ Therefore, The power of the complex number in the rectangular form is $-4+4\sqrt{3}i$.
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