Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.5 - Complex Numbers in Polar Form; DeMoivre's Theorem - Exercise Set - Page 768: 47

Answer

The division of the complex numbers in the polar form is $\frac{3}{4}\left( \cos \frac{\pi }{10}+i\sin \frac{\pi }{10} \right)$.

Work Step by Step

Here, $\begin{align} & {{z}_{1}}=3\left( \cos \frac{\pi }{5}+i\sin \frac{\pi }{5} \right) \\ & {{z}_{2}}=4\left( \cos \frac{\pi }{10}+i\sin \frac{\pi }{10} \right) \\ \end{align}$ Therefore $\begin{align} & \frac{{{z}_{1}}}{{{z}_{2}}}=\frac{3}{4}\left( \cos \left( \frac{\pi }{5}-\frac{\pi }{10} \right)+i\sin \left( \frac{\pi }{5}-\frac{\pi }{10} \right) \right) \\ & =\frac{3}{4}\left( \cos \frac{\pi }{10}+i\sin \frac{\pi }{10} \right) \end{align}$ The division of the complex numbers in the polar form is $\frac{3}{4}\left( \cos \frac{\pi }{10}+i\sin \frac{\pi }{10} \right)$
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