## Precalculus (6th Edition) Blitzer

The rectangular coordinates of $\left( 7.4,2.5 \right)$ are $\left( -5.9,4.4 \right)$.
The rectangular coordinates of the point are $\left( x,y \right)$. Now, rewrite the rectangular coordinates in terms of the polar coordinates: $x=r\cos \theta \ \text{ and }\ y=r\sin \theta$ …… (1) Substituting the values of $r\ \text{ and }\ \theta$ in (1) we get, \begin{align} & x=7.4\cos 2.5 \\ & \approx 7.4\left( -0.80 \right) \\ & \approx -5.9 \end{align} \begin{align} & y=7.4\sin 2.5 \\ & \approx 7.4\left( 0.60 \right) \\ & \approx 4.4 \end{align} Therefore, the rectangular coordinates of $\left( 7.4,2.5 \right)$ are $\left( -5.9,4.4 \right)$.