## Precalculus (6th Edition) Blitzer

Consider the given polar coordinate $\left( -3,-\frac{5\pi }{4} \right)$ as $\left( r,\theta \right)$. Here, \begin{align} & \theta =-\frac{5\pi }{4} \\ & r<0 \\ \end{align} From above, it is clear that $\theta$ has been taken in the clockwise direction and $r<0$, so $r$ lies opposite to the terminal side. Hence, $\left( -3,-\frac{5\pi }{4} \right)$ coordinate lies in the fourth quadrant.