## Precalculus (6th Edition) Blitzer

(a)$$(6, \frac{5\pi }{2})$$ (b)$$(-6, \frac{3\pi }{2})$$ (c)$$(6, -\frac{3\pi }{2})$$
To plot the point $(r, \theta )=(6, \frac{\pi }{2})$, begin with the $\frac{\pi }{2}$ angle. Because $\frac{\pi }{2}$ is a positive angle, draw $\theta = \frac{\pi }{2}$ counterclockwise from the polar axis. Now consider $r=6$. Because $r \gt 0$, plot the point by going out six units on the terminal side of $\theta$. Please note that if $n$ is any integer, the point $(r, \theta )$ can be represented as$$(r, \theta ) = (r, \theta +2n\pi ) \\ \text{or} \\ (r, \theta )= (-r, \theta +\pi + 2n\pi ).$$So we have (a)$$(6, \frac{\pi }{2})= (6, \frac{\pi }{2}+2(1)\pi)=(6, \frac{5\pi }{2}),$$(b)$$(6, \frac{\pi }{2})= (-6, \frac{\pi }{2}+\pi +2(0)\pi )=(-6, \frac{3\pi }{2}),$$(c)$$(6, \frac{\pi }{2})= (6, \frac{\pi }{2}+2(-1)\pi)=(6, -\frac{3\pi }{2}).$$