## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 6 - Section 6.3 - Polar Coordinates - Concept and Vocabulary Check - Page 741: 8

II

#### Work Step by Step

To plot the point $(r, \theta )=(-2, -\frac{\pi }{4})$, begin with the $-\frac{\pi }{4}$ angle. Because $-\frac{\pi }{4}$ is a negative angle, draw $\theta = -\frac{\pi }{4}$ clockwise from the polar axis. Now consider $r=-2$. Because $r \lt 0$, plot the point by going out two units along the ray opposite the terminal side of $\theta$. So, looking at the graph, we see that the point lies in the quadrant II.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.