Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.3 - Polar Coordinates - Concept and Vocabulary Check - Page 741: 8

Answer

II

Work Step by Step

To plot the point $(r, \theta )=(-2, -\frac{\pi }{4})$, begin with the $-\frac{\pi }{4}$ angle. Because $-\frac{\pi }{4}$ is a negative angle, draw $\theta = -\frac{\pi }{4}$ clockwise from the polar axis. Now consider $r=-2$. Because $r \lt 0$, plot the point by going out two units along the ray opposite the terminal side of $\theta$. So, looking at the graph, we see that the point lies in the quadrant II.
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