Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.3 - Polar Coordinates - Concept and Vocabulary Check - Page 741: 12


squaring; $x^2+y^2$

Work Step by Step

Please note that according to the definition of the trigonometric functions and by applying the Pythagorean theorem, we have the following relations between polar and rectangular coordinates:$$x=r\cos \theta, \qquad y=r\sin \theta, \\ r^2=x^2+y^2, \qquad \tan \theta =\frac{y}{x}.$$ Thus, the answers are: squaring; $x^2+y^2$
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