Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.3 - Polar Coordinates - Concept and Vocabulary Check - Page 741: 5

Answer

IV

Work Step by Step

To plot the point $(r, \theta )=(2, \frac{5\pi }{3})$, begin with the $\frac{5\pi }{3}$ angle. Because $\frac{5\pi }{3}$ is a positive angle, draw $\theta = \frac{5\pi }{3}$ counterclockwise from the polar axis. Now consider $r=2$. Because $r \gt 0$, plot the point by going out two units on the terminal side of $\theta$. So, looking at the graph, we see that the point lies in the quadrant IV.
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