Precalculus (6th Edition) Blitzer

Published by Pearson

Chapter 6 - Section 6.2 - The Law of Cosines - Exercise Set - Page 731: 49

Answer

$63.7\ ft$.

Work Step by Step

Using the figure as shown in triangle ABC, we have the angle $B=45^\circ$. Using the Law of Cosines, we have $b^2=90^2+60.5^2-2(90)(60.5)cos(45^\circ)\approx4060$ which gives $b\approx63.7\ ft$.

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