Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.2 - The Law of Cosines - Exercise Set - Page 731: 49

Answer

$63.7\ ft$.
1584666861

Work Step by Step

Using the figure as shown in triangle ABC, we have the angle $B=45^\circ$. Using the Law of Cosines, we have $b^2=90^2+60.5^2-2(90)(60.5)cos(45^\circ)\approx4060$ which gives $b\approx63.7\ ft$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.