## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 6 - Section 6.2 - The Law of Cosines - Exercise Set - Page 731: 44

#### Answer

Navigate $N 46^{\circ} W$

#### Work Step by Step

Using the law of cosines we can plug in the known information: $b^{2} = a^{2}+c^{2} - 2*a*c*cos\beta$ Since $a = 7, c=6$ and $b = 5$ we have: $25 = 49+36-84*cos\beta$ $25 = 85-84*cos\beta$ $cos\beta = 0.714$ $\beta \approx44^{\circ}$ Subtract $44^{\circ}$ from $90^{\circ}$ to get $46^{\circ}$.

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