Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.2 - The Law of Cosines - Exercise Set - Page 731: 48

Answer

$260.2\ ft$ and $239.3\ ft$
1585749443

Work Step by Step

Step 1. Draw a diagram as shown in the figure (not to scale). Step 2. For the left triangle, we have the angle $B=90^\circ+5^\circ=95^\circ$ Step 3. Using the Law of Cosines, we have $b^2=(200)^2+(150)^2-2(200)(150)cos95^\circ\approx67729$ Thus $b\approx260.2\ ft$ Step 4. For the right triangle, we have the angle $D=90^\circ-5^\circ=85^\circ$ Step 5. Using the Law of Cosines, we have $d^2=(200)^2+(150)^2-2(200)(150)cos85^\circ\approx 57271$ Thus $d\approx239.3\ ft$
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