## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 6 - Section 6.1 - The Law of Sines - Exercise Set - Page 723: 83

#### Answer

The graph is shown below: #### Work Step by Step

Consider that two airplanes leave an airport at the same time. The first plane is flying on a bearing of N66°W and travels 650 miles after two hours and the second plane is flying on a bearing of S26°W and travels 600 miles after two hours. Thus, the triangle illustrating the distance between two planes after two hours will be triangle $AOB$ with sides $AO$ and $BO$ with angle $AOB$. The angle $AOB$ is given by \begin{align} & 66{}^\circ +\angle AOB+26{}^\circ =180{}^\circ \\ & \angle AOB=180{}^\circ -92{}^\circ \\ & \angle AOB=88{}^\circ \end{align} Hence, the distance between the two planes after two hours would be denoted by the line segment AC in the following figure: After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.