#### Answer

The graph is shown below:

#### Work Step by Step

Consider that two airplanes leave an airport at the same time. The first plane is flying on a bearing of N66°W and travels 650 miles after two hours and the second plane is flying on a bearing of S26°W and travels 600 miles after two hours.
Thus, the triangle illustrating the distance between two planes after two hours will be triangle $AOB$ with sides $AO$ and $BO$ with angle $AOB$.
The angle $AOB$ is given by
$\begin{align}
& 66{}^\circ +\angle AOB+26{}^\circ =180{}^\circ \\
& \angle AOB=180{}^\circ -92{}^\circ \\
& \angle AOB=88{}^\circ
\end{align}$
Hence, the distance between the two planes after two hours would be denoted by the line segment AC in the following figure: