Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.1 - The Law of Sines - Exercise Set - Page 723: 60

Answer

the flagpole is leaning, $88^\circ$
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Work Step by Step

Step 1. See figure. Using the Law of Sines, we have $\frac{sinC}{15}=\frac{sin48^\circ}{16}$; thus $sinC=\frac{15sin48^\circ}{16}\approx 0.6967$ and $C=sin^{-1}0.6967\approx44^\circ$ or $C=180^\circ-44^\circ=136^\circ$ (discard this answer) Step 2. As $44^\circ+48^\circ=92^\circ\gt 90^\circ$, the flagpole is leaning. Step 3. We can find the angle as $B=180^\circ-92^\circ=88^\circ$
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