## Precalculus (6th Edition) Blitzer

The wingspan $C{C}'$ is $41\text{ feet}$.
At first we will reconstitute the graph as below: By observing the figure, we will find angle A: \begin{align} & A=180{}^\circ -150{}^\circ \\ & =30{}^\circ \end{align} Now, we will find d by using the law of sines: \begin{align} & \frac{d}{\sin A}=\frac{36}{\sin 90{}^\circ } \\ & \frac{d}{\sin 30{}^\circ }=\frac{36}{\sin 90{}^\circ } \\ & d=\frac{36\sin 30{}^\circ }{\sin 90{}^\circ } \\ & d=18 \end{align} Therefore, the wingspan $C{C}'$ is $18+5+18=41\text{ feet}$.