Answer
No such triangle exists.
Work Step by Step
For any triangle,
The law of sines states that:
$\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\operatorname{sinC}}$
Using the law of sines we get,
$\begin{align}
& \frac{a}{\sin A}=\frac{c}{\sin C} \\
& \frac{3}{\sin A}=\frac{1}{\sin 50{}^\circ } \\
& 3\cdot \sin 50{}^\circ =\sin A \\
& \sin A\approx 2.30
\end{align}$
Since, $\sin A\approx 2.30$ is not possible as the value of sine cannot exceed 1.
So, the triangle with this measure is not possible to construct.
Hence, no such triangle exists.
