Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Review Exercises - Page 798: 22

Answer

$(2,2\sqrt 3)$
1584097838

Work Step by Step

Step 1. See plot; move $\theta=60^\circ$, then $r=4$ to get the point. Step 2. Use the formulas $x=r\ cos\theta$ and $y=r\ sin\theta$; we have $x=4cos60^\circ =2$ and $y=4sin60^\circ=2\sqrt 3$, giving a point $(2,2\sqrt 3)$.
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