Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Review Exercises - Page 798: 23

Answer

$(-\frac{3\sqrt 3}{2}, \frac{3}{2})$
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Work Step by Step

Step 1. See plot; move $\theta=150^\circ$ then $r=3$ to get the point. Step 2. Use the formulas $x=r\ cos\theta$ and $y=r\ sin\theta$; we have $x=3cos150^\circ =-\frac{3\sqrt 3}{2}$ and $y=3sin150^\circ=\frac{3}{2} $, giving a point $(-\frac{3\sqrt 3}{2}, \frac{3}{2})$
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