Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Mid-Chapter Check Point - Page 756: 23

Answer

See below:

Work Step by Step

The provided equation in polar form is $ r=-3\csc \theta $ As $ x=r\cos \theta \ \text{ and }\ y=r\sin \theta $, $\begin{align} & r=-3\csc \theta \\ & r=\frac{-3}{\sin \theta } \\ & r\sin \theta =-3 \\ & y=-3 \end{align}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.