Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Mid-Chapter Check Point - Page 756: 21

Answer

The Cartesian form of the provided equation is ${{x}^{2}}+{{y}^{2}}={{6}^{2}}$.

Work Step by Step

The provided equation in polar form is $ r=6$ Therefore, ${{r}^{2}}=36$ As $ x=r\cos \theta \ \text{ and }\ y=r\sin \theta .$ Therefore, $\begin{align} & {{x}^{2}}+{{y}^{2}}={{r}^{2}}{{\cos }^{2}}\theta +{{r}^{2}}{{\sin }^{2}}\theta \\ & ={{r}^{2}}\left( {{\cos }^{2}}\theta +{{\sin }^{2}}\theta \right) \\ & ={{r}^{2}} \end{align}$ Thus, ${{x}^{2}}+{{y}^{2}}={{r}^{2}}$ Also, ${{r}^{2}}=36$ Therefore, $\begin{align} & {{x}^{2}}+{{y}^{2}}=36 \\ & {{x}^{2}}+{{y}^{2}}={{6}^{2}} \\ \end{align}$
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