Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Test - Page 709: 5


$\frac{\sqrt 6+\sqrt 2}{4}$

Work Step by Step

Using the subtraction formula, we have $sin(105^\circ)=sin(135^\circ-30^\circ)=sin(135^\circ) cos(30^\circ)-cos(135^\circ) sin(30^\circ)=(\frac{\sqrt 2}{2})(\frac{\sqrt 3}{2})-(-\frac{\sqrt 2}{2})(\frac{1}{2})=\frac{\sqrt 6+\sqrt 2}{4}$
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