Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Test - Page 709: 12



Work Step by Step

Step 1. Given the equation $sin(3x)=-\frac{1}{2}$, we can write the general solutions as $3x=2k\pi-\frac{\pi}{6}$ and $3x=2k\pi-\frac{5\pi}{6}$, where $k$ is an integer. Thus $x=\frac{2k\pi}{3}-\frac{\pi}{18}$ and $x=\frac{2k\pi}{3}-\frac{5\pi}{18}$ Step 2. We are restricted to find $x\in[0,2\pi)$, by testing $k$ values, we can find $x=\frac{7\pi}{18},\frac{11\pi}{18},\frac{19\pi}{18},\frac{23\pi}{18},\frac{31\pi}{18},\frac{35\pi}{18}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.