# Chapter 5 - Test - Page 709: 13

$\{\frac{\pi}{2}, \frac{7\pi}{6}, \frac{3\pi}{2}, \frac{11\pi}{6} \}$

#### Work Step by Step

Step 1. Rewrite the equation as $2sin(x)cos(x)+cos(x)=0$ or $cos(x)(2sin(x)+1)=0$ Step 2. For $cos(x)=0$, we can find $x=\frac{\pi}{2}, \frac{3\pi}{2}$ Step 3. For $sin(x)=-\frac{1}{2}$, we can find $x=\frac{7\pi}{6}, \frac{11\pi}{6}$ Step 4. The solution set is $\{\frac{\pi}{2}, \frac{7\pi}{6}, \frac{3\pi}{2}, \frac{11\pi}{6} \}$

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