Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Section 5.3 - Double-Angle, Power-Reducing, and Half-Angle Formulas - Exercise Set - Page 680: 40

Answer

The required value of $\cos 22.5{}^\circ $ is $\frac{\sqrt{2+\sqrt{2}}}{2}$.

Work Step by Step

We have to find the value of $\cos 22.5{}^\circ $; the formula is used which represents the cos identity. The term $\cos 22.5{}^\circ $ comes under the first quadrant where the value of all trigonometric functions is positive. And the value of the first quadrant is between $0{}^\circ \,\text{to}\,\text{90}{}^\circ $. $\begin{align} & \cos 22.5{}^\circ =\cos \frac{45{}^\circ }{2} \\ & =\sqrt{\frac{1+\cos 45{}^\circ }{2}} \\ & =\sqrt{\frac{1+\frac{\sqrt{2}}{2}}{2}} \\ & =\sqrt{\frac{2+\sqrt{2}}{2}} \end{align}$ Thus, the value of $\cos 22.5{}^\circ $ is $\frac{\sqrt{2+\sqrt{2}}}{2}$.
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