Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Section 5.3 - Double-Angle, Power-Reducing, and Half-Angle Formulas - Exercise Set - Page 680: 18

Answer

$-\frac{\sqrt 3}{2}$

Work Step by Step

Using the Double Angle Formula in reverse $cos^2\theta - sin^2\theta =cos2\theta$ we have $cos^2105^\circ - sin^2105^\circ =cos2(105^\circ)=cos210^\circ=-\frac{\sqrt 3}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.