Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Section 5.3 - Double-Angle, Power-Reducing, and Half-Angle Formulas - Exercise Set - Page 680: 16

Answer

$\frac{\sqrt 2}{2}$.

Work Step by Step

Recall the identity: $$\sin 2x=2\sin x \cos x$$ We apply this identity to the given equation: $$ 2 \sin 22.5 \cos 22.5= \sin2(22.5)=\sin45=\frac{\sqrt 2}{2}$$
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