Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.6 - Graphs of Other Trigonometric Functions - Exercise Set - Page 612: 93

Answer

$y=cot(\frac{3}{2}x)$

Work Step by Step

Step 1. This graph is similar to the cotangent function $y=cot(kx)$ Step 2. From the given period $\frac{2\pi}{3}$, we have $\frac{\pi}{k}=\frac{2\pi}{3}$, thus $k=\frac{3}{2}$ Step 3. The function is $y=cot(\frac{3}{2}x)$
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