Answer
This does not make sense.
Work Step by Step
Please note that in order to graph of $y=A\csc Bx$, one should use the graph of $y=A\sin Bx$.
So one should use the graph of $y=3\sin 2x$ to obtain the graph of $y=3\csc 2x$.
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 4 - Section 4.6 - Graphs of Other Trigonometric Functions - Exercise Set - Page 612: 91
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