## Precalculus (6th Edition) Blitzer

point-slope form:$$y-4=-3(x-(-3))$$ slope-intercept form:$$y=-3x-5$$
The line passing through the points $(-1, -2)$ and $(-3, 4)$ has slope$$m=\frac{4-(-2)}{-3-(-1)}=-3.$$So, by choosing the point $(-3, 4)$, the line has the point-slope form$$y-4=-3(x-(-3))$$and the slope-intercept form$$y-4=-3(x-(-3)) \quad \Rightarrow \quad y=-3x-5.$$