Answer
sin θ = $\frac{9}{41}$
cos θ = $\frac{40}{41}$
tan θ =$\frac{9}{40}$
csc θ = $\frac{41}{9}$
sec θ = $\frac{41}{40}$
cot θ = $\frac{40}{9}$
Work Step by Step
$a^{2}$ + $b^{y2}$ = $c^{2}$
given b= 40, c= 41
$a^{2}$ + $40^{2}$ = $41^{2}$
$a^{2}$ = 1681- 1600
$a^{2}$ = 81
a = $\sqrt {81}$ = 9
sin θ = $\frac{opposite}{hypotenuse}$ = $\frac{9}{41}$
cos θ = $\frac{adjacent}{hypotenuse}$ = $\frac{40}{41}$
tan θ = $\frac{opposite}{adjacent}$ = $\frac{9}{40}$
csc θ = $\frac{1}{sin θ}$ = $\frac{41}{9}$
sec θ = $\frac{1}{cos θ}$ = $\frac{41}{40}$
cot θ = $\frac{1}{tan θ}$ = $\frac{40}{9}$
