Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.3 - Right Triangle Trigonometry - Exercise Set: 3

Answer

sin θ = $\frac{20}{29}$ cos θ = $\frac{21}{29}$ tan θ =$\frac{20}{21}$ csc θ = $\frac{29}{20}$ sec θ = $\frac{29}{21}$ cot θ = $\frac{21}{20}$

Work Step by Step

$a^{2}$ + $b^{2}$ = $c^{2}$ given b = 21, c= 29 $a^{2}$ + $21^{2}$ = $29^{2}$ $a^{2}$ =841 - 441 $c^{2}$ = 400 c = $\sqrt {400}$ = 20 sin θ = $\frac{opposite}{hypotenuse}$ = $\frac{20}{29}$ cos θ = $\frac{adjacent}{hypotenuse}$ = $\frac{21}{29}$ tan θ = $\frac{opposite}{adjacent}$ = $\frac{20}{21}$ csc θ = $\frac{1}{sin θ}$ = $\frac{29}{20}$ sec θ = $\frac{1}{cos θ}$ = $\frac{29}{21}$ cot θ = $\frac{1}{tan θ}$ = $\frac{21}{20}$
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