Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.3 - Right Triangle Trigonometry - Exercise Set: 5

Answer

sin θ = $\frac{5}{13}$ cos θ = $\frac{12}{13}$ tan θ =$\frac{5}{12}$ csc θ = $\frac{13}{5}$ sec θ = $\frac{13}{12}$ cot θ = $\frac{12}{5}$

Work Step by Step

$a^{2}$ + $b^{y2}$ = $c^{2}$ given a= 10, c= 26 $10^{2}$ + $b^{2}$ = $26^{2}$ $b^{2}$ = 676- 100 $b^{2}$ = 576 b = $\sqrt {576}$ = 24 sin θ = $\frac{opposite}{hypotenuse}$ = $\frac{10}{26}$ = $\frac{5}{13}$ cos θ = $\frac{adjacent}{hypotenuse}$ = $\frac{24}{26}$ = $\frac{12}{13}$ tan θ = $\frac{opposite}{adjacent}$ = $\frac{10}{24}$ = $\frac{5}{12}$ csc θ = $\frac{1}{sin θ}$ = $\frac{13}{5}$ sec θ = $\frac{1}{cos θ}$ = $\frac{13}{12}$ cot θ = $\frac{1}{tan θ}$ = $\frac{12}{5}$
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