Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.2 - Exponential Functions - Exercise Set - Page 466: 139


False. $$\frac{\log_28}{\log_24}=\frac{3}{2}$$

Work Step by Step

As we know, $\log_ab^c=c\log_ab$. So we have$$\log_24=\log_22^2=2\log_22=2(1)=2 \\ \log_28=\log_22^3=3\log_22=3(1)=3$$Thus,$$\frac{\log_28}{\log_24}=\frac{3}{2}$$
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