Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.2 - Exponential Functions - Exercise Set - Page 466: 136

Answer

makes sense

Work Step by Step

This statement makes sense. As a matter of fact, $log_8(16)=\frac{log16}{log8}=\frac{log2^4}{log2^3}=\frac{4}{3}\approx1.33$
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