## Precalculus (6th Edition) Blitzer

This statement makes sense because an inverse of an exponential function is a logarithmic function. For example, $f(x)=2^x$ will have an inverse of $f^{-1}(x)=log_2(x)$. For $g(x)=2^x+1$, the horizontal asymptote shifts up from $y=0$ to $y=1$, while for $h(x)=log_2(x-2)$, the vertical asymptote shifts from $x=0$ to $x=2$