# Chapter 3 - Section 3.2 - Exponential Functions - Exercise Set - Page 464: 55

#### Work Step by Step

The graph of $h(x)=1+ \log_2x$ (the red graph) is the graph of $f(x)=\log_2x$ (the blue graph) shifted up one unit. Looking at the graph, we observe that the vertical asymptote is $x=0$. We also find that the domain and the range of the function $h(x)$ are$$D_h=(0, \infty ) \quad \text{ and } \quad R_h= (- \infty, \infty ),$$respectively.

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