## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 3 - Section 3.2 - Exponential Functions - Exercise Set - Page 464: 107

#### Answer

$2$

#### Work Step by Step

RECALL: (i) $\log_b{b}=1.$ (ii) $\log_b{b^x}=x.$ (iii) $\log_b{1} = 0.$ Note that $81=3^4$. Thus, the given expression can be written as $\log_2{(\log_3{3^4})}.$ Use rule (ii) above to obtain $\log_2{(\log_3{3^4})}=\log_2{4} = \log_2{2^2}.$ Use rule (ii) above to obtain $\log_2{2^2} =2.$

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