Precalculus (6th Edition) Blitzer

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RECALL: (i) $\log_b{b}=1$ (ii) $\log_b{b^x}=x$ (iii) $\log_b{1} = 0.$ Use rule (i) above to obtain $\log_3{(\log_7{7})} = \log_3{1}.$ Use rule (ii) above to obtain $\log_3{1} = 0.$