Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Review Exercises - Page 431: 78

Answer

vertical asymptote $x=\frac{3}{2}$. no horizontal asymptote. slant asymptote: $y=2x-5$ See graph.
1582726047

Work Step by Step

Step 1. Rewrite the function as $g(x)=\frac{4x^2-16x+16}{2x-3}=\frac{4x^2-6x-10x+15+1}{2x-3}=2x-5+\frac{1}{2x-3}$ Step 2. We can find a vertical asymptote as $x=\frac{3}{2}$. Step 3. There is no horizontal asymptote. Step 4. A slant asymptote can be found as $y=2x-5$ Step 5. See graph.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.