## Precalculus (6th Edition) Blitzer

$\frac{p}{q}=\pm1,\pm2,\pm4\pm8,\pm\frac{1}{3},\pm\frac{2}{3},\pm\frac{4}{3},\pm\frac{8}{3}$
Based on the Rational Zero Theorem, for the given function, we have $p=\pm1,\pm2,\pm4,\pm8$, $q=\pm1,\pm3$, and the possible rational zeros are $\frac{p}{q}=\pm1,\pm2,\pm4\pm8,\pm\frac{1}{3},\pm\frac{2}{3},\pm\frac{4}{3},\pm\frac{8}{3}$