## Precalculus (6th Edition) Blitzer

vertical asymptote $x=3$ no horizontal asymptote. slant asymptote $y=x+5$ See graph.
Step 1. Rewrite the function as $y=\frac{x^2+2x-3}{x-3}=\frac{x^2-3x+5x-15+12}{x-3}=x+5+\frac{12}{x-3}$ Step 2. The vertical asymptote can be found as $x=3$ Step 3. There is no horizontal asymptote. Step 4. A slant asymptote can be found as $y=x+5$ Step 5. See graph.