Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Test - Page 1180: 14



Work Step by Step

$ f^{,}(x)=\dfrac{df(x)}{dx}=10 \dfrac{d(x^{-1})}{dx}$ Since, $ \dfrac{d(x^{-1})}{dx}=(-1) x^{-2} = \dfrac{-1}{x^2}$ So, $ f^{,}(x)=\dfrac{-10}{x^2}$
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