Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Test - Page 1180: 13



Work Step by Step

$ f^{,}(x)=\dfrac{df(x)}{dx}=\dfrac{d(x^{2})}{dx}-5 \dfrac{dx}{dx}+\dfrac{d(1)}{dx}$ Since, $ \dfrac{d(x^{2})}{dx}=2x; \dfrac{dx}{dx}=1$ and $\dfrac{d(1)}{dx}=0$ So, $ f^{,}(x)=2x-5+0=2x-5$
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